33 lines
1005 B
Plaintext
33 lines
1005 B
Plaintext
let square = x -> x^2;
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let also_square(x) = x^2;
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let primes = range(100) |: filter(is_prime);
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let prime_squares = range(100) |: map(square);
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let also_prime_squares = range(100) |? is_prime |> square;
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#
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let primes_and_prime_squares = primes |& prime_squares;
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if 49 <~ data {
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println("49 is the square of a prime");
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} else {
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println("49 is not the square of a prime");
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}
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for p : primes {
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println(p);
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}
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# LET IDENT(square) EQ IDENT(x) ARROW IDENT(x) CARET INT(2) SEMICOLON
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#
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# LET IDENT(data) EQ IDENT(range) LPAREN INT(100) RPAREN PIPECOLON IDENT(filter) LPAREN IDENT(is_prime) RPAREN PIPECOLON IDENT(map) LPAREN IDENT(square) RPAREN SEMICOLON
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# LET IDENT(also_data) EQ IDENT(range) LPAREN INT(100) RPAREN PIPEQUESTION IDENT(is_prime) PIPEPOINT IDENT(square) SEMICOLON
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# D = x:(fold(map(factors(x), n:(to_int(fold(factors(x),mul)/n))), add))
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let D = x -> {
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let facts = factors(x);
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let product = facts |: foldl(1, mul);
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return facts |> (n -> product / n) |: foldl(0, add);
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}
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